有2个杯子，分别为5升和9升，在一个水池里有无限的水源，怎么才能在水池里拿到6升水呢
#includeusing namespace std;void print1(int,int,int);void print2(int,int,int);int main(){ int a, b, need; cout<<"输入两个杯子的容量及需要量出的水量：\n"; cin>>a>>b>>need; print1(a,b,need); print2(a,b,need); system("pause"); return 0;}void print1(int a, int b, int need){ int tmp,min,max,curMin,curMax; cout<<"\n\n逆容差算法：小杯子没水就装满水，大杯子水满了就倒掉，小杯子有水就往大杯子倒。然后判断大杯子水是否满足条件，不满足就继续\n\n"; if(a > b){ tmp = a; a = b; b = tmp; } min = a;//小杯子的容量 max = b;//大杯子的容量 curMin = 0;//当前小杯子里面有多少水 curMax = 0;//当前大杯子里面有多少水 //循环判断大杯子的水是否满足条件 cout<<"当前小杯子有"< <<"升水，当前大杯子有"< <<"升水\n"; while(curMax != need){ if(curMin == 0){ cout<<"小杯子没水了，装满水\n"; curMin = min; } else if (curMax == max){ cout<<"大杯子水满了，全倒掉\n"; curMax = 0; } else{ //将小杯子的水倒给大杯子，判断能倒多少水过去 tmp = max - curMax; tmp = tmp > curMin ? curMin : tmp; cout<<"将小杯子的水倒"< <<"升给大杯子\n"; curMax += tmp; curMin -= tmp; } cout<<"当前小杯子有"< <<"升水，当前大杯子有"< <<"升水\n"; } cout<<"当前大杯子的水满足条件，程序退出\n\n";}void print2(int a, int b, int need){ int tmp,min,max,curMin,curMax; cout<<"\n\n顺容差算法：大杯子没水就装满水，小杯子水满了就倒掉，大杯子有水就往小杯子倒。然后判断大杯子水是否满足条件，不满足就继续\n\n"; if(a > b){ tmp = a; a = b; b = tmp; } min = a;//小杯子的容量 max = b;//大杯子的容量 curMin = 0;//当前小杯子里面有多少水 curMax = 0;//当前大杯子里面有多少水 //循环判断大杯子的水是否满足条件 cout<<"当前小杯子有"< <<"升水，当前大杯子有"< <<"升水\n"; while(curMax != need){ if(curMax == 0){ cout<<"大杯子没水了，装满水\n"; curMax = max; } else if (curMin== min){ cout<<"小杯子水满了，全倒掉\n"; curMin = 0; } else{ //将大杯子的水倒给小杯子，判断能倒多少水过去 tmp = min- curMin; tmp = tmp > curMax ? curMax : tmp; cout<<"将大杯子的水倒"< <<"升给小杯子\n"; curMax -= tmp; curMin += tmp; } cout<<"当前小杯子有"< <<"升水，当前大杯子有"< <<"升水\n"; } cout<<"当前大杯子的水满足条件，程序退出\n\n";}